We are transmitting data at a rate of 6Mbps.

Question:

We are transmitting data at a rate of 6Mbps. During transmission, the noise introduces errors so that, on average, 3% of bits are received incorrectly (i.e.: a 0 as 1, or 1 as 0). The maximum error-free capacity of this channel is (in Mbps):

Summary:

Shannon’s theory is used to address the problem.
The channel’s maximum capacity (error-free) is 64.44 MHz.

Explanation:

Shannon’s theory can be used to tackle this problem.
The Shannon theory is used to compute the maximum amount of error-free information that can be transferred per unit of time over a communication link with a specified bandwidth in the presence of noise interference.

B = 6Mbps is the given bandwidth.

The error rate is 3%, meaning that 3% of bits are received wrongly.

SNR = 10(97/30) = 103.233 = 1710

C = B * log(SNR) = 6 * 106 * log(1710) = 6 * 106 * 10.7397 = 64438683.6588 Hz = 64.439 MHz

SNR = 10(97/30) = 103.233 = 1710

C = B * log(SNR) = 6 * 106 * log(1710) = 6 * 106 * 10.7397 = 64438683.65

Also, read the Given below-defined UML class diagram.