Simplify this expression using Boolean algebra rules.

Question

Can you help me simplify this expression below using Boolean algebra rules and also can you state your step and rules used, please?
(z’+y)yz

Summary

Here in this question, we are going to simplify the given expression using Boolean algebra rules and also state the step and rules used.

Explanation

The given expression in the question is

= (z’+y)yz

When we will Use Distributive Law, A(B+C)=AB+AC. At that time we get

= z’yz + y.yz

Using Inverse Law, A.A’=0 and Idempotent law, A.A=A. At that time we will get

= 0.y + y.z

And Using NULL Law, A.0=0, we have

= 0 + y.z

Using Identity law, 0+A=A, we get

= yz

Thus, the complete solution for the given expression is

= (z’+y)yz      –  Distributive law
= z’yz + yyz   –  Inverse law and Impotence law
= 0.y + y.z     –  Null law
= 0 +yz          –  Identity law
= yz

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